Question

Cho (a-1)/2=(b+3)/4=(c-5)/6 va 5a-3b-4c=46.xac dinh a;b;c

Answer 1

\(\Rightarrow\frac{5\left(a-1\right)}{5.2}=\frac{3.\left(b+3\right)}{3.4}=\frac{4.\left(c-5\right)}{4.6}\Rightarrow\frac{5a-5}{10}=\frac{3b+9}{12}=\frac{4c-20}{24}=\frac{5a-5-\left(3b+9\right)-\left(4c-20\right)}{10-12-24}\)

\(\Rightarrow\frac{5a-5}{10}=\frac{3b+9}{12}=\frac{4c-20}{24}=\frac{5a-5-\left(3b+9\right)-\left(4c-20\right)}{10-12-24}=\frac{\left(5a-3b-4c\right)-5-9+20}{-26}=\frac{46+6}{-26}=-2\)

+) \(\frac{5a-5}{10}=-2\Rightarrow5a-5=-20\Rightarrow a=-3\)

+) \(\frac{3b+9}{12}=-2\Rightarrow3b+9=-24\Rightarrow b=-11\)

+) \(\frac{4c-20}{24}=-2\Rightarrow4c-20=-48\Rightarrow c=-7\)

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