\(n_{Zn}=\dfrac{6,5}{65}=0,1\left(mol\right)\\
pthh:Zn+2HCl\rightarrow ZnCl_2+H_2\)
0,1 0,1 0,1
\(V_{H_2}=0,1.22,4=2,24l\\
m_{HCl}=100.14,6\%=14,6g\\
m_{\text{dd}}=6,5+100-\left(0,1.2\right)=106,3g\\
C\%=\dfrac{0,1.136}{106,3}.100\%=12,8\%\)
\(n_{Zn}=\dfrac{6,5}{65}=0,1\left(mol\right)\\
pthh:Zn+2HCl\rightarrow ZnCl_2+H_2\)
0,1 0,1 0,1
\(V_{H_2}=0,1.22,4=2,24l\\
m_{ZnCl_2}=0,1.127=12,7g\\
m_{\text{dd}}=6,5+100-\left(0,1.2\right)=64,8g\\
C\%=\dfrac{12,7}{64,8}.100\%=19,6\%\)