a/3=b/8=c/5
=>2a/6=3b/24=c/5
áp dụng tc dãy ts = nhau ta có :
2a/6=3b/24=c/5=2a+3b-c/6+24-5=50/25=2
=>a/3=2=>a=6
=>b/8=2=>b=16
=>c/5=2=>c=10
=>a+b+c=6+16+10=32
cho cac so a,b,c va thoa man \(\frac{ab}{a+b}=\frac{1}{3},\frac{bc}{b+c}=\frac{1}{4},\frac{ca}{c+a}=\frac{1}{5}\)Tinh gia tri bieu thuc P=\(\frac{1}{a}+\frac{1}{b}+\frac{1}{c}\)
cau 1: Cho A= \(\frac{100^{2014}+2}{3}-\frac{100^{2015}+17}{9}.\)tong cac cua so cua B=-9A
Cau 2: So sanh A=\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+........+\frac{1}{100.101}\)voi 1 ta doc A....1
Cau 3 : Cho bon so a,b,c,d sao cho a+b+c+d khac 0 . Biet \(\frac{b+c+d}{a}=\frac{c+d+a}{b}=\frac{d+a+b}{c}=\frac{a+b+c}{d}=k\). Vay k=
Cau 4 : so cac so nguyen am x thoa man \(x^{2015}=\left(-2\right)^{2014}\)
Cau 5; tim x,y,z biet \(\frac{x}{y}=\frac{10}{9},\frac{y}{z}=\frac{3}{4}\)va x-y+z=78
Cau 6: tap hop cac so co ba chu so chia het cho 18 va tong cac chu so ti le voi 1;2;3 la
Cau 7: gia tri cua tong S=1.2+2.3+.....+49.50 la S=
Cho a,b,c là cac so thoa man dieu kien \(\frac{2a-b}{a+b}=\frac{b-c+a}{2a-b}=\frac{2}{3}\)
Khi đo gia tri cua bieu thuc \(P=\frac{\left(5b+4a\right)^5}{\left(5b+4c\right)^2.\left(a+3c\right)^3}\)
Cho cac so a,b,c va thoa man\(\frac{a}{a+b}+\frac{b}{b+c}+\frac{c}{c+a}=2\)Tinh gia tri bieu thuc \(P=\frac{b}{a+b}+\frac{c}{b+c}+\frac{a}{c+a}\)
cho a,b,c,d la 4 so khac 0 thoa man b^2 =ac va c^2=bd.Cmr\(\frac{a^3+b^3+c^3}{b^3+c^3+d^3}\)=\(\frac{a}{b}\)
Cau 1; cho\(\frac{x}{2}=\frac{y}{5}\)vaxy=90. So cap (x;y) thoa man la
Cau 2 : Cho a+d=b+c va \(a^2+d^2=b^2+c^2\)(b,d khac 0).Khi do 4 so lap thanh ti le thuc nao
Cau 3 :GTLN cua phan so \(\frac{7n-8}{2n-3}\)
Cau 4: Cho A=\(\frac{12}{x-15}\) dieu kien de 0<A<1 va A>1
Cau 5 ; tim x biet /-x-5//x=5=10
Cau 6: tap hop cac so nguyen cua x thoa man (3x^2-51)^2014=(-24)^2014
Cau 7: tap hop cac so thoa man /x-y/+/y+9/25/=0
Tìm a,b,c biết :
\(\frac{a}{3}=\frac{b}{8}=\frac{c}{5}\) và 2a + 3b - c = 50
Gia su a,b,c la cacso thoa man a+b+c=259 va \(\frac{1}{a+b}+\frac{1}{b+c}+\frac{1}{a+c}=15\). Khi do gia tri cua bieu thuc \(Q=\frac{a}{b+c}+\frac{b}{a+c}+\frac{c}{a+b}\)bang
bai 1
xac dinh dau cua c ,biet rang 2a\(^3\)bc trai dau voi -3a\(^5\)b\(^3\)c\(^2\)
bai 2
cho day ti so bang nhau
\(\frac{2a+b+c+d}{a}=\frac{a+2b+c+d}{b}=\frac{a+b+2c+d}{c}=\frac{a+b+c+2d}{d}\)
tinh gia tri bieu thuc m voi
m=\(\frac{a+b}{c+d}=\frac{b+c}{d+a}=\frac{c+d}{a+b}=\frac{d+a}{b+c}\)
