\(\left(x+\dfrac{1}{5}\right)^2+\dfrac{13}{25}=\dfrac{17}{25}\\ \Leftrightarrow\left(x+\dfrac{1}{5}\right)^2=\dfrac{4}{25}\\ \Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{5}=\dfrac{2}{5}\\x+\dfrac{1}{5}=-\dfrac{2}{5}\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{5}\\x=-\dfrac{3}{5}\end{matrix}\right.\)