Question

c,

\(\frac{3.7-3.19}{3.4}\)

d,\(\frac{2^3.9^4-2^4.3^7}{2^{4.3^7}}\)

Answer 1

c) \(\frac{3\cdot7-3\cdot19}{3\cdot4}=\frac{3\left(7-19\right)}{3\cdot4}=\frac{3\cdot\left(-12\right)}{3\cdot4}=\frac{3\cdot4\cdot\left(-3\right)}{3\cdot4}=-3\)

Vậy \(\frac{3\cdot7-3\cdot19}{3\cdot4}=-3\)

d,\(\frac{2^3\cdot9^4-2^4\cdot3^7}{2^4\cdot3^7}=\frac{2^3\cdot\left(3^2\right)^4-2^4\cdot3^7}{2^4\cdot3^7}=\frac{2^3\cdot3^8-2^4\cdot3^7}{2^2\cdot3^7}=\frac{2^3\cdot3^7\left(3-2\right)}{2^2\cdot3^7}=2\)

Answer 2

bạn làm đúng rồi nhé

chúc bạn học tốt@