Question

C=\(\frac{1,5+1-0,75}{2,5+1-0,25}\)

Tính C

Answer 1

\(C=\frac{1,5+1-0,75}{2,5+1-0,25}\)

\(\Rightarrow C=\frac{2,5-0,75}{3,5-0,25}\)

\(\Rightarrow C=\frac{1,75}{3,25}\)

\(\Rightarrow C=\frac{7}{13}\)

Vậy \(C=\frac{7}{13}\)

Answer 2

C=\(\frac{1,5+1-0,75}{2,5+1-0,25}\)

  =\(\frac{\left(1,5+1-0,75\right).4}{\left(2,5+1-0,25\right).4}\)

  =\(\frac{6+4-3}{10+4-1}\)

  =\(\frac{7}{13}\)

Học tốt nha!!!