Các câu hỏi tương tự
các bạn giúp mik bài này vs
5) (4x-5).(x+2)-(x+5).(x-3)-3x^2-x
6) (x-3).(x+7)-(2x-1).(x+2)+x.(x-1)
7) (7x-3).(2x+1)-(5x-2).(x+4)-9x^2+17x
8) -2.(x-7).(x+3)+(5x-1).(x+4)-3x^2-27x
9) (6x-5).(x+8)-(3x-1).(2x+3)-9.(4x-3)
10) (8x-1).(x+7)-(x-2).(8x+5)-11.(6x+1).
Nhóm nhiều hạng tử
a) (x - 1)(2x + 1) + 3(x - 1)( x + 2 )
b) (6x + 3) - (2x - 5)(2x + 1)
c) (x - 5)2 + (x + 5)(x - 5) - (5 - x)(2x + 1)
e) (3x - 2)(4x - 3) - (2 - 3x)( x - 1) - 2(3x - 2)(x + 1)
Bài 2 Tìm x 1,. ( x+1 ) (x+ 3 ) - x ( x+ 2 ) =7 2,. 2x ( 3x + 5 ) - x ( 6x - 1 ) =33 3,. ( 3x^2 - x +1 ) ( x - 1) + x^2 ( 4 - 3x ) = 5/2 Giúp em với mn !
a,(3x - 1)(x + 3) = (2 - x)(5 - 3x)
b,(x + 5)(2x - 1) = (2x - 3)(x + 1)
c,(x + 1)(x + 9) = (x + 3)(x + 5)
d,(3x + 5)(2x + 1) = (6x - 2)(x - 3)
e,(x + 2)2 + 2(x - 4) = (x - 4)(x - 2)
f,(x + 1)(2x - 3)-(3x - 2) = 2(x - 1)2
Bài 1. Thu gọn:a) x2 – 4 – (x + 2)2b) (x + 2)(x – 2) – (x – 3)(x + 1)c) (x – 2)(x + 2) – (x – 2)(x + 5)d) (6x + 1)2 + (6x – 1)2 – 2(6x + 1)(6x – 1)e) 7a(3a – 5) + (2a -3)(4a + 1) – (6a – 2)2g) (5y – 3)(5y + 3) – (5y – 4)2h) (3x + 1)3 – (1 – 2x)3i) (2x + 1)2 + 2(4x2 – 1) + (2x – 1)2
Đọc tiếp
Bài 1. Thu gọn:
a) x2 – 4 – (x + 2)2 | b) (x + 2)(x – 2) – (x – 3)(x + 1) |
c) (x – 2)(x + 2) – (x – 2)(x + 5) | d) (6x + 1)2 + (6x – 1)2 – 2(6x + 1)(6x – 1) |
e) 7a(3a – 5) + (2a -3)(4a + 1) – (6a – 2)2 | g) (5y – 3)(5y + 3) – (5y – 4)2 |
h) (3x + 1)3 – (1 – 2x)3 | i) (2x + 1)2 + 2(4x2 – 1) + (2x – 1)2 |
Phân tích các đa thức sau thành nhân tử
a, (x-3)(x-1)-3(x-3)
b, (x-1)(2x+1)+3(x-1)(x+2)(2x+1)
c, (6x+3)-(2x-5)(2x+1)
d, (x-5)^2+(x+5)(x-5)-(5-x)(2x+1)
e, (3x-2)(4x-3)-(2-3x)(x-1)-2(3x-2)(x+1)
3x^4 + 3x^2y^2 + 6x^3y - 27x^2
x^4 + x^3 - x^2 + x
2x^5 - 6x^4 - 2a^2x^3 - 6ax^3
x^5 + x^4 + x^3 + x^2 + x + 1
x^3 - 1 + 5x^2 - 5 + 3x - 3
1/4.(a + 1)^2 - 4/9.(a - 2)^2
12a^2b^2 - 3.(a^2b^2)^2
4x^2y^2 - (x^2 + y^2 - a^2)^2
(a + b + c)^2 + (a + b - c)^2 - 4c^2
x^3 - 1 + 5x^2 - 5 + 3x - 3
. Tìm x, biết:
a) 6x.(x – 5) + 3x.(7 – 2x) = 18 b) 2x.(3x + 1) + (4 – 2x).3x = 7 c) 0,5x.(0,4 – 4x) + (2x + 5).x = -6,5 | d) (x + 3)(x + 2) – (x - 2)(x + 5) = 6 e) 3(2x - 1)(3x - 1) – (2x - 3)(9x - 1) = 0 |
Tìm x
a.(x+2).(x+3)-(x-2).(x+5) = 0
b. (2x+3).(x-4)+(x-5)(x+2) = (3x-5)(x-4)
c. (3x+2)(2x+9)-(x+2)(6x+1) = x+1-(x-6)
d. 3( 2x-1).(3x-1)-(2x-3).(9x-1)=0