Question

Câu 3: Tìm x, biết. a) 5x(x – 2) – 3(x – 2) = 0 b) (x – 2)^2 – (x – 1)(x + 3) = 1

giúp mik pls

Answer 1

a) 5x(x-2) - 3(x-2) = 0

<=> (x-2) (5x-3) = 0

<=> TH1: x - 2 = 0 

          <=> x=2

       TH2: 5x-3 = 0

           <=> x= 3/5

b) (x-2)^2 - (x-1)(x+3)=1

<=> (x²-4x+2) - (x²+3x-x-3) = 1

<=> x²-4x+4-x²-3x+x+3=1
<=> -4x-3x+x= 1-4-3

<=> -6x=-6

<=> x= 1

Answer 2

x=1 nha

HT

k cho mình nha

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Answer 3

a, \(5x\left(x-2\right)-3\left(x-2\right)=0\Leftrightarrow\left(5x-3\right)\left(x-2\right)=0\Leftrightarrow x=\frac{3}{5};x=2\)

b, \(\left(x-2\right)^2-\left(x-1\right)\left(x+3\right)=1\)

\(\Leftrightarrow x^2-4x+4-x^2+2x+3=1\Leftrightarrow-2x=-6\Leftrightarrow x=3\)