Câu 1 Tim số nguyên x, biet rằng
\(4\frac{1}{3}.\left(\frac{1}{6}-\frac{1}{2}\right)\le\times\le\frac{2}{3}.\left(\frac{1}{2}-\frac{1}{2}-\frac{3}{4}\right)\)
Câu 2 : Tính
\(1\frac{13}{15}.0,75-\left(\frac{104}{195}+25\%\right).\frac{24}{47}-3\frac{12}{13}:3\)
Câu 3 ; Tìm x Biet
\(\left(\frac{1}{12}+3\frac{1}{6}-30,75\right).\times-8=\left(\frac{3}{5}+0,415+\frac{1}{200}\right):0,01\)
Câu 4 : So Sánh \(A=\frac{10^8+2}{10^8-1}\);
Câu 2 :
\(1\frac{13}{15}.0,75-\left(\frac{104}{195}+25\%\right).\frac{24}{47}-3\frac{12}{13}:3\)
\(\frac{28}{15}.\frac{3}{4}-\left(\frac{104}{195}+\frac{25}{100}\right).\frac{24}{47}-\frac{51}{13}:3\)
\(\frac{28}{15}.\frac{3}{4}-\frac{47}{60}.\frac{24}{47}-\frac{51}{13}:3\)
\(\frac{7}{5}-\frac{2}{5}-\frac{51}{13}.\frac{1}{3}\)
\(\frac{7}{5}-\frac{2}{5}-\frac{17}{13}\)
\(-\frac{4}{13}\)
Câu 1:
\(-\frac{13}{9}\le x\le-\frac{1}{2}\)
\(x=-1\)
1
\(4\frac{1}{3}.\left(\frac{1}{6}-\frac{1}{2}\right)=4\frac{1}{3}.-\frac{1}{3}=-\frac{13}{9}=-1,444..\)
\(\frac{2}{3}.\left(\frac{1}{2}-\frac{1}{2}-\frac{3}{4}\right)=\frac{2}{3}.\left(-\frac{3}{4}\right)=-\frac{1}{2}=-0,5\)
Mà \(\times\)nguyên => x \(\in\){-1}
\(\left(\frac{1}{12}+3\frac{1}{6}-30,75\right).\times-8=\left(\frac{3}{5}+0,415+\frac{1}{200}\right):0,01\)
\(\left(\frac{1}{12}+3\frac{1}{6}-30,75\right).\times-8=\frac{121}{200}:0,01\)
\(\left(\frac{1}{12}+3\frac{1}{6}-30,75\right).\times-8=60,5\)
\(\left(\frac{1}{12}+3\frac{1}{6}-30,75\right).\times=60,5+8\)
\(\left(\frac{1}{12}+3\frac{1}{6}-30,75\right).\times=68,5\)
\(x=68,5:\left(\frac{1}{12}+3\frac{1}{6}-30,75\right)\)
\(x=68,5:-27,5\)
\(x=-2,4\)
khong lam duoc thi thoi vo day noi ba náp ba spam