<=> (x-1)/99-1 + (x-2)/49-2 + (x-7)/31-3 +(x-8)/23-4=0
<=> (x-100)/99 + (x-100)/49 + (x-100)/31 + (x-100)/23=0
<=> (x-100)(1/99 + 1/49 + 1/31 + 1/23)=0
<=> x-100=0(vì 1/99 + 1/49 + 1/31 +1/23)
<=> x=100
Vậy PT có TN S={100}
giải PT: a, (4x-5)2 (2x-3)(x-1)=9
b,\(\frac{5}{x-8}+1=\frac{23}{x^2-5x-24}+\frac{2}{x+3}\)
c,(\(\left(\frac{x-1}{99}+\frac{x-99}{1}\right)+\left(\frac{x-3}{97}+\frac{x+97}{3}\right)+\left(\frac{x-5}{93}+\frac{x-95}{5}\right)=6\)
Giải các pt sau:
a, \(\frac{x+5}{4}-\frac{2x-3}{3}=\frac{6x-1}{8}+\frac{2x-1}{12}\)
b,\(\frac{\left(x+10\right)\left(x+4\right)}{12}-\frac{\left(x+4\right)\left(2-x\right)}{4}=\frac{\left(x+10\right)\left(x-2\right)}{3}\)
Giúp mình với ạ
Giải phương trình:
a,\(\frac{5-x}{4x^2-8x}+\frac{7}{8x}=\frac{x-1}{2x\left(x-2\right)}+\frac{1}{8x-16}\)
b,\(\frac{x-49}{50}+\frac{x-50}{49}=\frac{49}{x-50}+\frac{50}{x-49}\)
c,\(\frac{1}{x\left(x+1\right)}+\frac{1}{\left(x+1\right)\left(x+2\right)}+\frac{1}{\left(x+2\right)\left(x+3\right)}=\frac{1}{x+3}\)
1) giải phương trình:
a) \(\left(2x+3\right)\left(\frac{3x+8}{2-7x}+1\right)=\left(x+5\right)\left(\frac{3x+8}{2-7x}+1\right)\)
b) \(\frac{7x+10}{x+1}\left(x^2-x-2\right)-\frac{7x+10}{x+1}\left(2x^2-3x-5\right)=0\)
c) \(\frac{2x+5}{x+3}+1=\frac{4}{x^2+2x-3}-\frac{3x-1}{1-x}\)
d) \(\frac{13}{2x^2+x-21}+\frac{1}{2x+7}+\frac{6}{9-x^2}=0\)
e) \(\frac{x-49}{50}+\frac{x-50}{49}=\frac{49}{x-50}+\frac{50}{x-49}\)
f) \(\frac{1+\frac{x}{x+3}}{1-\frac{x}{x+3}}=3\)
\(\frac{\left(x-1\right)^2}{x^2}+\frac{\left(x-1\right)^2}{\left(x-2\right)^2}=\frac{40}{49}\)
Giải PT
giải pt sau
a)\(\frac{3}{7}x-1=\frac{1}{7}x\left(3x-7\right)\)
b)\(\left(3x-1\right)\left(x^2+2\right)=\left(3x-1\right)\left(7x-10\right)\)
giải các pt sau
\(\frac{x+1}{3}+\frac{3\left(2x+1\right)}{4}=\frac{2x+3\left(x+1\right)}{6}+\frac{7+12x}{12}\)
\(\frac{2\left(3x+1\right)+1}{4}-5=\frac{2\left(3x-1\right)}{5}-\frac{3x+2}{10}\)
\(\frac{3\left(x-3\right)}{4}+\frac{4x-10.5}{10}=\frac{3\left(x+1\right)}{5}+6\)
\(\frac{x+1}{58}+\frac{x+2}{57}=\frac{x+3}{56}+\frac{x+4}{55}\)
\(\frac{2x+9}{\left(x+1\right)\left(x+8\right)}-\frac{2x+15}{\left(x+8\right)\left(x+7\right)}+\frac{2x+10}{\left(x+7\right)\left(x+3\right)}=\frac{4}{3}\)
1. \(\frac{7}{8}x-5\left(x-9\right)=\frac{20x+1,5}{6}\)
2 . \(\frac{\left(2x+1\right)^2}{5}-\frac{\left(x+1\right)^2}{3}=\frac{7x^2-14x-5}{15}\)
3 . \(4\left(3x-2\right)-3\left(x-4\right)=7x+10\)
4. \(\frac{\left(x+10\right)\left(x+4\right)}{12}-\frac{\left(x+4\right)\left(2-x\right)}{4}=\frac{\left(x+10\right)\left(x-2\right)}{3}\)
