\(\frac{x}{7}=\frac{x+16}{35}\)
\(\Leftrightarrow x\cdot35=7\left(x+16\right)\)
\(\Leftrightarrow35x=7x+112\)
\(\Leftrightarrow35x-7x=112\)
\(\Leftrightarrow28x=112\)
\(\Leftrightarrow x=4\)
Vậy x = 4
\(\frac{8}{x}=\frac{7}{x-16}\)
\(\Leftrightarrow8\left(x-16\right)=x\cdot7\)
\(\Leftrightarrow8x-128=7x\)
\(\Leftrightarrow8x-7x=128\)
\(\Leftrightarrow x=128\)
Vậy x = 128
a,\(\frac{x}{7}=\frac{x+16}{35}< =>\frac{5x}{35}=\frac{x+16}{35}\)
\(< =>5x=x+16\)
\(< =>4x=16< =>x=4\)
b,\(\frac{8}{x}=\frac{7}{x-16}\)\(< =>8x-128=7x\)
\(< =>x=128\)
thanks ban nhieu!!!
\(\frac{x}{7}=\frac{x+16}{35}\)
\(\Rightarrow x.35=7\left(x+16\right)\)
\(\Rightarrow35x=7x+112\)
\(\Rightarrow35x-7x=112\)
\(\Rightarrow28x=112\)
\(\Rightarrow x=112:28=4\)
Vậy \(x=4\)
\(\frac{8}{x}=\frac{7}{x-16}\)
\(\Rightarrow8\left(x-16\right)=7x\)
\(\Rightarrow8x-128=7x\)
\(\Rightarrow8x-7x=128\)
\(\Rightarrow x=128\)
Vậy \(x=128\)
Học tốt
\(a,\frac{x}{7}=\frac{x+16}{35}\)
\(35x=7\left(x+16\right)\)
\(35x=7x+112\)
\(35x-7x=112\)
\(\left(35-7\right)x=112\)
\(28x=112\)
\(x=4\)
\(a,\frac{8}{x}=\frac{7}{x-16}\)
\(8\left(x-16\right)=7x\)
\(8x-128=7x\)
\(8x-7x=128\)
\(x=128\)
