(x + 1 ) + ( x + 2 ) + ( x + 3 ) + ........+ (x + 100) = 5550
x = 100 + ( 1 + 2 + 3 + .........+100)=5550
x = (5550 - 5050 ) : 100
x = 500 : 100
x = 5
lethanhthao em lấy đâu ra 5550 đầu bài ko có bị thiếu
#)Giải :
Cho mk sửa lại đề là tổng trên = 5750 nha
\(\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+...+\left(x+100\right)=5750\)
\(\left(x+x+x+...+x\right)+\left(1+2+3+...+100\right)=5750\)
\(\left(x.100\right)+\left(100+1\right)x100:2=5750\)
\(\left(x.100\right)+5050=5750\)
\(x.100=5750-5050\)
\(x.100=700\)
\(x=700:100\)
\(x=7\)
#~Will~be~Pens~#
bạn RJ thiếu đề bài bạn Lethanhthao bổ sung ạ
Ta có: \(\left(x+1\right)+\left(x+2\right)+...+\left(x+100\right)=5550\)
\(100x+\left(1+2+...+100\right)=5550\)
\(100x+5050=5550\)
\(100x=500\)
\(x=5\)
Vậy \(x=5\)
\(\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+...+100=5550\)
\(\left(x+x+x+...+x\right)+\left(1+2+3+...+100\right)=5550\)
\(100x+\left[\left(100-1\right)\text{ : }1+1\right]\text{ x }\left(100+1\right)\text{ : }2=5550\)
\(100x+\frac{100\text{ x }101}{2}=5550\)
\(100x+5050=5550\)
\(100x=5550-5050\)
\(100x=500\)
\(x=500\text{ : }100\)
\(x=5\)