\(\dfrac{2}{3}\)-\(\dfrac{1}{5}\)=\(\dfrac{10}{15}\)-\(\dfrac{3}{15}\)=\(\dfrac{7}{15}\)
\(\dfrac{2}{3}-\dfrac{1}{5}=\dfrac{15}{10}-\dfrac{3}{15}=\dfrac{7}{15}\)
nếu là cộng
\(\dfrac{2}{3}\)+\(\dfrac{1}{5}\)=\(\dfrac{10}{15}\)+\(\dfrac{3}{15}\)=\(\dfrac{13}{15}\)
cộng là:
\(\dfrac{2}{3}+\dfrac{1}{5}=\dfrac{10}{15}+\dfrac{3}{15}=\dfrac{13}{15}\)