\(\left(x-1\right)=\left(2x-3\right)^2\)
\(\Leftrightarrow x-1=4x^2-12x+9\)
\(\Leftrightarrow4x^2-13x+10=0\)
\(\Leftrightarrow4x^2-8x-5x+10=0\)
\(\Leftrightarrow4x.\left(x-2\right)-5.\left(x-2\right)=0\)
\(\Leftrightarrow\left(x-2\right)\left(4x-5\right)=0\)
\(\Leftrightarrow\hept{\begin{cases}x-2=0\\4x-5=0\end{cases}}\Leftrightarrow\hept{\begin{cases}x=2\\x=\frac{5}{4}\end{cases}}\)
Vậy: \(x=2\)hoặc \(x=\frac{5}{4}\)(Nếu đúng thì click cho mình nhoa!)
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