Question

C=1/5+1/5^2+1/5^3+....+1/5^300

Giúp mk nhé***

Answer 1

\(C=\frac{1}{5}+\frac{1}{5^2}+\frac{1}{5^3}+....+\frac{1}{5^{300}}\)

\(5C=1+\frac{1}{5}+\frac{1}{5^2}+...+\frac{1}{5^{299}}\)

\(5C-C=1-\frac{1}{5^{300}}\)

\(4C=1-\frac{1}{5^{300}}\)

\(C=\frac{1-\frac{1}{5^{300}}}{4}\)

Answer 2

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Answer 3

   \(C=\frac{1}{5}+\frac{1}{5^2}+\frac{1}{5^3}+...+\frac{1}{5^{300}}\)

\(5C=5.\left(\frac{1}{5}+\frac{1}{5^2}+\frac{1}{5^3}+...+\frac{1}{5^{300}}\right)\)

\(5C=5.\frac{1}{5}+5.\frac{1}{5^2}+5.\frac{1}{5^3}+...+5.\frac{1}{5^{300}}\)

\(5C=1+\frac{1}{5}+\frac{1}{5^2}+...+\frac{1}{5^{299}}\)

\(5C-C=\left(1+\frac{1}{5}+\frac{1}{5^2}+...+\frac{1}{5^{299}}\right)-\left(\frac{1}{5}+\frac{1}{5^2}+\frac{1}{5^3}+...+\frac{1}{5^{300}}\right)\)

\(4C=1+\frac{1}{5}+\frac{1}{5^2}+...+\frac{1}{5^{299}}-\frac{1}{5}-\frac{1}{5^2}-\frac{1}{5^3}-...-\frac{1}{5^{300}}\)

\(4C=1-\frac{1}{5^{300}}\)

\(C=\frac{1-\frac{1}{5^{300}}}{4}\)

Answer 4

Cảm ơn!!! Mk kết bạn nhé