\(\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+...+\frac{1}{x\cdot\left(x+1\right)}=\frac{3}{10}\)
\(\Rightarrow\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+...+\frac{1}{x}-\frac{1}{x+1}=\frac{3}{10}\)
\(\Rightarrow\frac{1}{3}-\frac{1}{x+1}=\frac{3}{10}\)
\(\Rightarrow\frac{1}{x+1}=\frac{1}{3}-\frac{3}{10}\)
\(\Rightarrow\frac{1}{x+1}=\frac{1}{30}\)
\(\Rightarrow x=30-1\)
\(\Rightarrow x=29\)
vậy: \(x=29\)