Question

Bỏ ngoặc rồi tính:

f. (36 + 79) + (145 - 79 - 36)

g. 10 - [12 - (-9 - 1]

h. (38 - 29 + 43) - (43 + 38)

i. 271 - [(-43) + 271 - (-17)]

k. -144 - [29 - (+144) - (+144)]

Answer 1

f,(36+79)+(145-79-36)

=36+79+145-79-36

=(36-36)+(79-79)+145

=0+0+145

=145

g,10-[12-(-9-1)]

=10-(12+9+1)

=10-(12+10)

=10-12-10

=(10-10)-12

=0-12

=-12

h,(38-29+43)-(43+38)

=38-29+43-43-38

=(38-38)-29+(43-43)

=0-29+0

=-29

i,271-[(-43)+271-(-17)]

=271-(-43+271+17)

=271+43-271-17

=(271-271)+(43-17)

=0+26

=26

k,-144-[29-(+144)-(+144)]

=-144-(29-144-144)

=-144-29+144+144

=(-144+144)-29+144

=0-29+144

=-29+144

=115

Answer 2

f)=145

g)= -12

h)= -29

i)=26

k)=115