Question

Bỏ dấu ngoặc rồi tính :

a) (56 - 27) - ( 11 + 28 - 16)

b) 28 + ( 19 - 28) - (32 - 57)

Answer 1

a) (56 - 27) - (11 + 28 - 16) 

= 56 - 27 - 11 - 28 + 16 

= (56 + 16) – (27 + 11 + 28)

= 72 – (38 + 28)

= 72 – 66

= 6

b) 28 + (19 - 28) - (32 - 57) 

= 28 + 19 – 28 – 32 + 57

= (28 – 28) + (19 + 57) – 32

= 0 + 76 – 32

= 76 - 32

= 44

  

Answer 2

a) (56 - 27) - (11 + 28 - 16) 

= 56 - 27 - 11 - 28 + 16 

= (56 + 16) – (27 + 11 + 28)

= 72 – (38 + 28)

= 72 – 66

= 6

b) 28 + (19 - 28) - (32 - 57) 

= 28 + 19 – 28 – 32 + 57

= (28 – 28) + (19 + 57) – 32

= 0 + 76 – 32

= 76 - 32

= 44

Answer 3

A) 6

B) 44

Answer 4

Đây nhé!

a) (56 - 27) -(11+28 -16)

= 56 - 27 - 11+28 - 16

= (56+16) - (27+11+28)

= 72 - (38+28)

= 72 - 66

= 6

b) 28+(19 - 28) - (32 - 57)

= 28+19 - 28 - 32+57

= (28 - 28)+(19+57) - 32

= 0+76 - 32

= 76 - 32

= 44