Question

B=\(\frac{9^{12}.4^8}{27^7.2^{17}}\)

mình đang cần gấp ai giúp mình với

Answer 1

\(B=\frac{9^{12}\cdot4^8}{27^7\cdot2^{17}}\)

\(B=\frac{\left(3^2\right)^{12}\cdot\left(2^2\right)^8}{\left(3^3\right)^7\cdot2^{17}}\)

\(B=\frac{3^{24}\cdot2^{16}}{3^{21}\cdot2^{17}}\)

\(B=\frac{3^3}{2}\)

\(B=\frac{27}{2}\)

Answer 2

\(B=\frac{9^{12}.4^8}{27^7.2^{17}}\)

\(\Rightarrow B=\frac{\left(3^2\right)^{12}.\left(2^2\right)^8}{\left(3^3\right)^7.2^{17}}\)

\(\Rightarrow B=\frac{3^{24}.2^{16}}{3^{21}.2^{17}}\)

\(\Rightarrow B=\frac{3^3}{2}=\frac{27}{2}\)