\(\frac{\left(\frac{2}{5}\right)^7.5^7+\left(\frac{9}{3}\right)^3:\left(\frac{3}{16}\right)^3}{2^7.27+512}=\frac{\left(\frac{2}{5}.5\right)^7+\left(\frac{9}{3}:\frac{3}{16}\right)^3}{128.27+512}\)
\(=\frac{2^7+16^3}{3456+512}=\frac{128+4096}{3968}=\frac{4224}{3968}=\frac{33}{31}\)