Question

Bài3Tính giá trị biểu thức

a) A=\(\frac{3^{10}.11+3^{10}.5}{3^9.2^4}\)

b) B=\(\frac{2^{10}.13+2^{10}.65}{2^8.104}\)

c) C=\(\frac{72^3.54^2}{108^4}\)

d) D=\(\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)

Answer 1

A= 3^10.( 11+5 ) / 3^9. 2^4 

A= 3^10. 16 /3 ^9 . 16

A= 3^10/3^9= 3

B= 2^10. ( 13 +65) / 2^8.104

B= 2^10. 78/ 2^8.104

B= 2 ^10.2.39/ 2^8 .2.52

B= 2^11.39/ 2^9.52

B= 2 ^ 2. (39/ 52)

B= 4 . 39/52 = 3

C= (2^3.3^2)^3.( 2.3.3^2 )^2 / (2^2.3^3)^4

C= 2^9.3^6/ 2^2.3^2.3^4

C= 2^9.3^6/ 2^2.3^6

C= 2^9/2^2= 2^5=32

D= 11.3^29-3^30/ 2^2.3^28

D= 3^29.(1- 3)/ 2^2.3^28

D= 3^29.(-2)/ 2^2.3^28

D= 3. (-2/2^2)

D = 3. (-1/2)= -3/2