c.từ 7 đến 43 có:(43-7):4+1=10(số)
từ 7 đến 43 có 10 số=>có 10 số X
[X+7]+[X+11]+[X+15]+...+[X+43]=1980
X*10+(7+11+15+...+43)=1980
X*10+250=1980
X*10=1980-250
X*10=1730
X=1730:10
X=173
c.từ 7 đến 43 có:(43-7):4+1=10(số)
từ 7 đến 43 có 10 số=>có 10 số X
[X+7]+[X+11]+[X+15]+...+[X+43]=1980
X*10+(7+11+15+...+43)=1980
X*10+250=1980
X*10=1980-250
X*10=1730
X=1730:10
X=173
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