a)\(\frac{16x25+44\text{x}100}{29\text{x}96+142\text{x}48}\)
=\(\frac{4\text{x}4\text{x}25+11\text{x}4\text{x}4\text{x}25}{29\text{x}2\text{x}48+71\text{x}\text{ }2\text{x}48}\)
=\(\frac{\left(1+11\right)x4\text{x}4\text{x}25}{\left(29+71\right)x2\text{x}48}\)
=\(\frac{12\text{x}4\text{x}100}{100\text{x}2\text{x}48}\)
=\(\frac{48\text{x}100}{48\text{x}100\text{x}2}\)
=\(\frac{1}{2}\)