Question

bài 6

b, 2x +(-461)-(231-416)

d, 211-(123-x)+(123-211)

Answer 1

B) 2x + (-416) - (231 - 416 )

= 2x - 416 - 231 + 416

= 2x - ( 416 +231 - 416 )

= 2x - 231

D) 211-(123-x)+(123-211)

= 211 - 123 + x + 123 - 211

= ( 211 - 123 +123 - 211 )+ x

= 0+ x

= x

Answer 2

b) 2x + (-461) - (231 - 416)

= 2x - 461 - (231 - 416)

= 2x - 461 + 185

= 2x - 276

d) 211 - (123 - x) + (123 - 211)

= 211 - 123 + x + 123 - 211

= (211 - 211) + (-123 + 123) + x

= 0 + 0 + x

= x