Các câu hỏi tương tự
rút gọn biểu thức:
P = \(\left(\frac{x^2-3x}{x^3+3x^2+9x+27}+\frac{3}{x^2+9}\right):\left(\frac{1}{x-3}-\frac{6x}{x^3-3x^2+9x-27}\right)\)
\(\left(\frac{X^2+3X}{X^3+3X^2+9X+27}+\frac{3}{X+9}\right):\left(\frac{1}{X-3}-\frac{6X}{X^3-3X^2+9X-27}\right)\)
Rút gọn
a) \(\left(\frac{4}{x^3-9x}+\frac{1}{x+3}\right):\left(\frac{x-3}{x^2+3x}-\frac{x}{3x+9}\right)\)
b) \(\left(\frac{2}{x-2}-\frac{2}{x+2}\right).\frac{x^2+4x+4}{8}\)
c) \(\left(\frac{3x}{1-3x}+\frac{2x}{3x+1}\right):\frac{6x^2+10x}{1-6x+9x^2}\)
Cho biểu thức \(M=\left(1-\frac{6-2x^3}{x^6-9}\right).\frac{4}{x^5+3x^2}:\left(\frac{6x^6-24}{x^9+6x^6+9x^3}:\left(\frac{3x^2}{2}+\frac{3}{x}\right)\right)\)
a/ Rút gọn M
b/ Tìm các giá trị nguyên của x để M đạt GTLN. Tìm GTLN đó
Q= \(\left(x^3-1-\frac{7-x^3}{3+x^3}\right).\frac{4}{x^5+3x^2}:\left(\frac{6x^4-24}{x^9+6x^6+9x^3}.\frac{2x}{3x^3+6}\right)\)
R/g\(\left[\left(x^3-1\right)-\frac{7-x^3}{3+x^3}.\frac{4}{x^5+3x^2}\right]:\left[\frac{3x^6-12}{x^9+6x^6+9x^3}.\frac{x}{3x^3+6}\right]\)
Trừ phân thức
a) \(\frac{1}{3x-2}-\frac{1}{3x+2}-\frac{3x-6}{4-9x^2}\)
b) \(\frac{18}{\left(x-3\right)\left(x^2-9\right)}-\frac{3}{x^2-6x+9}-\frac{x^2}{x^2-9}\)
A=\(\left(\frac{3-x}{x+3}.\frac{x^2+6x+9}{x^2-9}+\frac{x}{x+3}\right):\frac{3x^2}{x+3}\)
rút gọn A
Thực hiện phép tính:a)frac{2x+6}{3x^2-x}:frac{x^2+3x}{1-3x}b)frac{x+3}{x}-frac{x}{x-3}+frac{9}{x^2-3x}c)frac{x+3}{x^2-1}-frac{1}{x^2+x}d)frac{1}{3x-2}-frac{4}{3x+2}-frac{-10x+8}{9x^2-4}e)frac{3}{2x^2+2x}+frac{2x-1}{x^2-1}-frac{2}{x}f)left(frac{9}{x^3-9x}+frac{1}{x+3}right):left(frac{x-3}{x^2+3x}-frac{x}{3x+9}right)g)frac{8}{left(x^2+3right)left(x^2-1right)}+frac{2}{x^2+3}+frac{1}{x+1}
Đọc tiếp
Thực hiện phép tính:
a)\(\frac{2x+6}{3x^2-x}:\frac{x^2+3x}{1-3x}\)
b)\(\frac{x+3}{x}-\frac{x}{x-3}+\frac{9}{x^2-3x}\)
c)\(\frac{x+3}{x^2-1}-\frac{1}{x^2+x}\)
d)\(\frac{1}{3x-2}-\frac{4}{3x+2}-\frac{-10x+8}{9x^2-4}\)
e)\(\frac{3}{2x^2+2x}+\frac{2x-1}{x^2-1}-\frac{2}{x}\)
f)\(\left(\frac{9}{x^3-9x}+\frac{1}{x+3}\right):\left(\frac{x-3}{x^2+3x}-\frac{x}{3x+9}\right)\)
g)\(\frac{8}{\left(x^2+3\right)\left(x^2-1\right)}+\frac{2}{x^2+3}+\frac{1}{x+1}\)