Question

BÀi 4 : 

c) ( \(\frac{1}{1x3}\)+\(\frac{1}{3x5}\)+.......+\(\frac{1}{19x21}\)) x 63 - x = 20 

làm nhanh giùm mik nha mấy bạn , mik đg cần gấp bây giờ ^-_-^

Answer 1

(1/1-1/3+1/3-1/5+...+1/19-1/20)*63-x=20

(1/1-1/20)*63-x=20

19/20*63-x=20

1177/20-x=20

58,85-x=20

x=58,85-20

x=38,85

kich dung nha

Answer 2

              Đặt \(A=\frac{1}{1.3}+\frac{1}{3.5}+...+\frac{1}{19.21}\)

              \(2A=\frac{2}{1.3}+\frac{2}{3.5}+...+\frac{2}{19.21}\)

             \(2A=1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+...+\frac{1}{19}-\frac{1}{21}\)

              \(2A=1-\frac{1}{21}\)

              \(A=\frac{20}{21}:2\)

            \(A=\frac{10}{21}\)

          => \(\frac{10}{21}\)x 63 - x = 20

         => 30 - x = 20

        => x = 30 - 20 = 10

      Vậy x = 10

     Ủng hộ mk nha !!! ^_^

            

Answer 3

\(A=\frac{1}{1.3}+\frac{1}{3.5}+...+\frac{1}{19.21}\)

\(2A=\frac{2}{1.3}+\frac{2}{3.5}+...+\frac{2}{19.21}\)

\(2A=1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+...+\frac{1}{19}-\frac{1}{21}\)

\(2A=1-\frac{1}{21}\)

\(A=\frac{20}{21}:2\)

> $\frac{10}{21}$1021 x 63 - x = 20

         => 30 - x = 20

        => x = 30 - 20 = 10

      Vậy x = 10