Question

bài 2: phân tích đa thức thành nân tử

a, x⁴-y⁴

e, (4x²-4x+1)-(x+1)²

g, 27x³-0.001

c, (3x-2y)²(2x-3y)²

k, 125x³-1

Answer 1

a) x⁴ - y⁴

= (x²)² - (y²)²

= (x² - y²)(x² + y²)

= (x - y)(x + y)(x² + y²)

Answer 2

a.\(x^4-y^4=\left(x^2\right)^2-\left(y^2\right)^2=\left(x^2-y^2\right)\left(x^2+y^2\right)=\left(x-y\right)\left(x+y\right)\left(x^2+y^2\right)\)g,\(27x^3-0.001=27x^3-0=27x^3\)

Answer 3

a: \(=\left(x^2-y^2\right)\left(x^2+y^2\right)\)

\(=\left(x-y\right)\left(x+y\right)\left(x^2+y^2\right)\)

e: \(=\left(2x-1\right)^2-\left(x+1\right)^2\)

\(=\left(2x-1-x-1\right)\left(2x-1+x+1\right)\)

\(=3x\left(x-2\right)\)

g: \(=\left(3x-\dfrac{1}{10}\right)\left(9x^2+\dfrac{3}{10}x+\dfrac{1}{100}\right)\)

k: \(=\left(5x-1\right)\left(25x^2+5x+1\right)\)