Question

Bài 1:Cho x/2 = y/3= z/4 và xyz =192. Tìm x,y,z

 

Answer 1

Đặt \(\frac{x}{2}=\frac{y}{3}=\frac{z}{4}=k\Rightarrow\hept{\begin{cases}x=2k\\y=3k\\z=4k\end{cases}}\)

\(\Rightarrow xyz=2k\cdot3k\cdot4k=24k^3=192\)

\(\Rightarrow k^3=8=2^3\)

\(\Rightarrow k=2\)

\(\Rightarrow\hept{\begin{cases}\frac{x}{2}=2\\\frac{y}{3}=2\\\frac{z}{4}=2\end{cases}}\Rightarrow\hept{\begin{cases}x=4\\y=6\\z=8\end{cases}}\)

Vậy x = 4; y = 6; z = 8

Answer 2

Đặt \(\frac{x}{2}=\frac{y}{3}=\frac{z}{4}=k\Rightarrow x=2k;y=3k;z=4k\)

\(xyz=192\Rightarrow24k^3=192\Rightarrow k^3=8\Rightarrow k=2\)

\(\Rightarrow x=2.2=4\)

\(y=2.3=6\)

\(z=2.4=8\)