a. 2/3 xy2z.(-3x2y)2
b. x2yz.(2xy)2z
Lời giải:
a. Ta có: 2/3 xy2z.(-3x2y)2 = - 2/3 xy2z.9x4y2
= (-2/3 .9)(x.x4).(y2.y2).z = -6x5y4z
b. Ta có: x2yz.(2xy)2z = x2yz.4x2y2.z = 4(x2.x2)(y.y2)(z.z) = 4x4y3z2
a. 2/3 xy2z.(-3x2y)2
b. x2yz.(2xy)2z
Lời giải:
a. Ta có: 2/3 xy2z.(-3x2y)2 = - 2/3 xy2z.9x4y2
= (-2/3 .9)(x.x4).(y2.y2).z = -6x5y4z
b. Ta có: x2yz.(2xy)2z = x2yz.4x2y2.z = 4(x2.x2)(y.y2)(z.z) = 4x4y3z2
\(\frac{2}{3}xy^2z.\left(-3x^2y\right)^2\)
\(=-\frac{2}{3}xy^2z.9x^4y^2\)
\(=\left(-\frac{2}{3}.9\right)\left(x.x^4\right)\left(y^2y^2\right).z\)
\(=-6x^5y^4z\)
\(x^2yz.\left(2xy\right)^2z\)
\(=x^2yz.4x^2y^2.z\)
\(=4\left(x^2x^2\right)\left(yy^2\right)\left(zz\right)\)
\(=4x^4y^3z^2\)
