a, \(5\frac{3}{4}:\frac{5}{6}-3\frac{3}{4}:\frac{5}{6}\)
\(=\left(5\frac{3}{4}-3\frac{3}{4}\right):\frac{5}{6}\)
\(=2\frac{3}{4}:\frac{5}{6}\)
\(=\frac{11}{4}.\frac{6}{5}\)
\(=\frac{66}{20}\)
\(=\frac{33}{10}\)
b, \(\frac{4}{5}.\frac{22}{47}+\frac{25}{47}:\frac{5}{4}\)
\(=\frac{4}{5}.\frac{22}{47}+\frac{25}{47}.\frac{4}{5}\)
\(=\frac{4}{5}.\left(\frac{22}{47}+\frac{25}{47}\right)\)
\(=\frac{4}{5}.1\)
\(=\frac{4}{5}\)
a) 5\(\frac{3}{4}\) : \(\frac{5}{6}\) - 3\(\frac{3}{4}\) : \(\frac{5}{6}\)
= ( 5\(\frac{3}{4}\) - 3\(\frac{3}{4}\) ) : \(\frac{5}{6}\)
= 2 : \(\frac{5}{6}\) = \(\frac{12}{5}\)
b) \(\frac{4}{5}\) x \(\frac{22}{47}\)+ \(\frac{25}{47}\) : \(\frac{5}{4}\)
= \(\frac{4}{5}\) x \(\frac{22}{47}\) + \(\frac{25}{47}\) x \(\frac{4}{5}\)
= \(\frac{4}{5}\) x ( \(\frac{22}{47}\) + \(\frac{25}{47}\) )
= \(\frac{4}{5}\) x 1 = \(\frac{4}{5}\)
\(a,5\frac{3}{4}\div\frac{5}{6}-3\frac{3}{4}\div\frac{5}{6}=\frac{23}{4}\cdot\frac{6}{5}-\frac{15}{4}\cdot\frac{6}{5}\)
\(=\left(\frac{23}{4}-\frac{15}{4}\right)\cdot\frac{6}{5}\)
\(=\frac{8}{4}\cdot\frac{6}{5}\)
\(=\frac{8\cdot6}{4\cdot5}=\frac{12}{5}\)
\(b,\frac{4}{5}\times\frac{22}{47}+\frac{25}{47}\div\frac{5}{4}=\frac{4}{5}\times\frac{22}{47}+\frac{25}{47}\times\frac{4}{5}\)
\(=\left(\frac{22}{47}+\frac{25}{47}\right)\times\frac{4}{5}\)
\(=\frac{47}{47}\times\frac{4}{5}=\frac{4}{5}\)
Tk mh nhé , mơn nhìu !!!
~ HOK TỐT ~