Question

bài 1: tính các tổng sau theo cách hợp lý

A = 1+5 +5^2 +5^3 +...+5^1998

B=4+4^2 +4^3 +.....+4^n

 

Answer 1

\(A=\)\(1+5+5^2+5^3+...+5^{1998}\)

\(5A=5+5^2+5^3+5^4+...+5^{1999}\)

\(5A-A=\left(5+5^2+5^3+5^4+...+5^{1999}\right)-\left(1+5+5^2+5^3+...+5^{1998}\right)\)

\(4A=5^{1999}-1\)

\(\Rightarrow A=\frac{5^{1999}-1}{4}\)

\(B=4+4^2+4^3+...+4^n\)

\(4B=4^2+4^3+4^4+...+4^{n+1}\)

\(4B-B=\left(4^2+4^3+4^4+...+4^{n+1}\right)-\left(4+4^2+4^3+...+4^n\right)\)

\(3B=4^{n+1}-4\)

\(\Rightarrow B=\frac{4^{n+1}-4}{3}\)

Answer 2

thucs the