Bài 1
A= \(\frac{81^{10}.3^{17}}{27^{10}.9^{13}}\)
= \(\frac{\left(3^4\right)^{10}.3^{17}}{\left(3^3\right)^{10}.\left(3^2\right)^{13}}\)
= \(\frac{3^{40}.3^{17}}{3^{30}.3^{26}}\)
= \(\frac{3^{57}}{3^{56}}\)= 3
\(\frac{x}{7}\)= \(\frac{-12}{49}\)
=> 49x = (-12) x 7
=> 49x = -84
=> x= \(\frac{-12}{7}\)
1) \(A=\frac{3^{40}.3^{17}}{3^{30}.3^{26}}=\frac{3^{57}}{3^{56}}=3\)
2) \(\Leftrightarrow49x=-84\Rightarrow x=-\frac{12}{7}\)
k mik nha bn, tks
bài 1:
\(A=\frac{\left(3^4\right)^{10}.3^{17}}{\left(3^3\right)^{10}.\left(3^2\right)^{13}}=\frac{3^{40}.3^{17}}{3^{30}.3^{26}}=\frac{3^{57}}{3^{56}}=3\)
