bai 1 Tim x,y
a, (x-3)x+3 =(x-3)x+13
b,\(\frac{5x-1}{3}=\frac{7y-6}{5}=\frac{5x-4y-7}{4x}\)
c,|x+5|=(3y-4)2016
tìm x,y biết : \(\frac{5x-1}{3}=\frac{7y-6}{5}=\frac{5x-7y-7}{4x}\)
Tìm x, y biết :
\(\frac{5x-1}{3}=\frac{7y-6}{5}=\frac{5x+7y}{4x}\)= 7
Tìm x, biết:\(\frac{5x-1}{3}=\frac{7y-6}{5}=\frac{5x-7y-7}{4x}\)
tim x;y
\(\frac{5x-1}{3}=\frac{7y-6}{5}=\frac{5x+7y-7}{4x}\)
\(\frac{5x-1}{3}\)= \(\frac{7y-6}{5}\)= \(\frac{5x-7y-7}{4x}\).Tìm x,y
Tìm x,y
a, \(\frac{5x-1}{3}=\frac{7y-6}{5}=\frac{5x-4y-7}{4x}\)
b, |x+5|=(3y-4)2016
cac ban giup minh minh hau ta bao cach like that nhieu cho nguoi ay
\(\frac{5x-1}{3}\)= \(\frac{7y-6}{5}\)= \(\frac{5x+7y-7}{4x}\)
Tìm x,y,z
\(\text{Tìm x,y}:\frac{5x-1}{3}=\frac{7u-6}{5}=\frac{5x-4y-7}{4x}\) :