a)Ta có: (2x - 1)6 = (2x - 1 )8
=> (2x - 1) . (2x - 1) . (2x - 1) . (2x - 1) . (2x - 1) . (2x - 1) = (2x - 1) . (2x - 1) . (2x - 1) . (2x - 1) . (2x - 1) . (2x - 1) . (2x - 1) . (2x - 1)
=> 2x - 1 = 0; 1
+ Nếu 2x - 1 = 0
=> 2x = 1
=> x = 1/2
+ Nếu 2x - 1 = 1
=> 2x = 2
=> x = 1