\(a,97-7\left(x-11\right)=34\)
\(7\left(x-11\right)=63\)
\(x-11=9\)
\(x=20\)
Vậy \(x=20\).
\(b,4^3-\left(25+x\right)=6^2\)
\(64-\left(25+x\right)=36\)
\(25+x=28\)
\(x=3\)
Vậy \(x=3.\)
\(c,\left|x-5\right|-9=-3\)
\(\left|x-5\right|=6\)
\(\Rightarrow\orbr{\begin{cases}x-5=-6\\x-5=6\end{cases}\Rightarrow\orbr{\begin{cases}x=-1\\x=11\end{cases}}}\)
Vậy \(x\in\left\{-1;11\right\}\).
a) Ta có : 97 - 7 . ( x - 11 ) = 34
<=> 7. ( x -1 ) = 97 - 34
<=> 7. ( x - 1 ) = 63
<=> x - 1 = 63 : 7
<=> x - 1 = 9
<=>x = 9 + 1
<=> x = 10
Vậy x = 10
b)Cách 1 : Ta có : 43 - ( 25 + x ) = 62
<=> 64 - ( 25 + x ) = 36
<=> 25 + x = 64 -36
<=> x = 28 - 25
<=> x = 3
Vậy x = 3
Cách 2 :Ta có : 43 - ( 25 + x ) = 62
<=> 64 - 25 -x = 36
<=> 39 -x = 36
<=> x = 39 - 36
<=> x = 3
Vậy x = 3
c)Ta có : | x - 5 | - 9= -3
<=>| x - 5 | = ( -3 ) + 9
<=> | x - 5| = 6
\(\Leftrightarrow\orbr{\begin{cases}x-5=6\\x-5=-6\end{cases}\Leftrightarrow\orbr{\begin{cases}x=11\\x=-1\end{cases}}}\)
Vậy x = { 11 ; -1 }
a, 97 - 7( x - 11) = 34
<=> 97 - 7x + 77 =34
<=> -7x = 34 - 97 - 77
<=>-7x = -140
<=> x = 20
Vậy_
\(a)97-7\left(x-11\right)=34\)
\(\Rightarrow7\left(x-11\right)=97-34\)
\(\Rightarrow7\left(x-11\right)=63\)
\(\Rightarrow x-11=9\)
\(\Rightarrow x=20\)
\(b)4^3-\left(25+x\right)=6^2\)
\(\Rightarrow64-\left(25+x\right)=36\)
\(\Rightarrow25+x=28\)
\(\Rightarrow x=3\)
\(c)\left|x-5\right|-9=-3\)
\(\Rightarrow\left|x-5\right|=6\)
\(\Rightarrow\orbr{\begin{cases}x-5=6\\x-5=-6\end{cases}\Rightarrow\orbr{\begin{cases}x=11\\x=-1\end{cases}}}\)
