\(\dfrac{5x+7}{10x-1}=\dfrac{2x+9}{4x-5}\)
\(\Rightarrow\left(5x+7\right)\left(4x-5\right)=\left(10x-1\right)\left(2x+9\right)\)
\(\Rightarrow20x^2+3x-35=20x^2+98x-9\)
\(\Rightarrow3x-35=98x-9\)
\(\Rightarrow-95x=26\)
\(\Rightarrow x=\dfrac{-26}{95}\)

