Question

Bài 1: Tìm x

a,(2x-3)²-10x²+15x=0

b,49.(x-5)²-4.(2x+1)=0

c,(x+6)²-8x-48=0

d,64.(2x+3)²-(x-6)²=0

Answer 1

a: \(\Leftrightarrow\left(2x-3\right)^2-5x\left(2x-3\right)=0\)

=>(2x-3)(-3x-3)=0

=>x=-1 hoặc x=3/2

b: \(\Leftrightarrow49\left(x^2-10x+25\right)-8x-4=0\)

=>\(49x^2-498x+1221=0\)

=>\(x\in\left\{6.03;4.13\right\}\)

c: \(\Leftrightarrow\left(x+6\right)\left(x+6-8\right)=0\)

=>(x-2)(x+6)=0

=>x=2 hoặc x=-6

d: =>\(\left(16x+24\right)^2-\left(x-6\right)^2=0\)

=>(16x+24+x-6)(16x+24-x+6)=0

=>(17x+18)(15x+30)=0

=>x=-2 hoặc x=-18/17