a)\(5^{30}=\left(5^2\right)^{15}=25^{15}\)
Ta có: \(25^{15}< 124^{15}< 124^{18}\)
\(\Rightarrow5^{30}< 124^{18}\)
b) \(4^{21}=\left(4^3\right)^7=64^7\)
c) \(874^2=\left(870+4\right).874=870.874+4.874\)
\(870.878=870.\left(874+4\right)=870.874+870.4\)
Ta có: \(\left(870+4\right).874>870.874+4.870\)
\(\Rightarrow874^2>870.878\)
Tham khảo nhé~
a) \(5^{30}\) và \(124^{18}\)
\(5^{30}=\left(5^5\right)^6=3125^6\)
\(124^{18}=\left(124^3\right)^6=1906624^6\)
Vì \(3125< 1906624\)
Vậy \(5^{30}< 124^{18}\)
b) \(4^{21}\) và \(64^7\)
\(4^{21}=\left(4^3\right)^7=64^7\)
Vì \(64=64\)
Vậy \(4^{21}=64^7\)
c) \(874^2\) và \(870.878\)
\(874^2=874.874=763876\)
\(870.878=763860\)
Vì \(763876>763860\)
Vậy \(874^2>870. 878\)
