\(\frac{x}{9}=\frac{y}{12}=\frac{z}{13}\left(x< y< z\right)\)
\(x+y+z=51\)
\(\Rightarrow\frac{x}{9}=\frac{y}{12}=\frac{z}{13}=\frac{x+y+z}{9+12+13}=\frac{51}{34}=\frac{3}{2}\)
\(\Rightarrow\hept{\begin{cases}x=\frac{27}{2}\\y=18\\z=\frac{39}{2}\end{cases}}\)