Bài 1:
a ) \(\dfrac{x}{5}=\dfrac{y}{7}\& x.y=140\)
b) \(\dfrac{x}{5}=\dfrac{y}{3}=\dfrac{z}{2} \& 3x-2y+7z=69\)
c) \(\dfrac{x}{5}=\dfrac{y}{4} \& x^2-y^2=1\)
d) \(5x=7y\&y-x=18\)
Giúp mk nhé :
Trần Thị Yến Nhi Phạm Hoàng Giang Nguyễn Huy Tú Ace Legona Akai Haruma
a)
\(\dfrac{x}{5}=\dfrac{y}{7}=k\\ \Rightarrow\left\{{}\begin{matrix}x=5k\\y=7k\end{matrix}\right.\)
\(x.y=5k.7k=35k^2=140\\ \Rightarrow k^2=4\Rightarrow k=\pm2\)
\(\Rightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}x=10\\y=14\end{matrix}\right.\\\left\{{}\begin{matrix}x=-10\\y=-14\end{matrix}\right.\end{matrix}\right.\)
b)
\(\dfrac{x}{5}=\dfrac{y}{3}=\dfrac{z}{2}\Rightarrow\dfrac{3x}{15}=\dfrac{2y}{6}=\dfrac{7z}{14}=\dfrac{3x-2y+7z}{15-6+14}=\dfrac{69}{23}=3\)
\(\Rightarrow\left\{{}\begin{matrix}x=15\\y=9\\z=6\end{matrix}\right.\)
B.3x/15=2y/6=7z/14
3x-2y+7z/15-6+14=69/23=3
...
c)
\(\dfrac{x}{5}=\dfrac{y}{4}\Rightarrow\dfrac{x^2}{25}=\dfrac{y^2}{16}=\dfrac{x^2-y^2}{25-16}=\dfrac{1}{9}\)
\(\Rightarrow\left\{{}\begin{matrix}x=\dfrac{5}{9}\\y=\dfrac{4}{9}\end{matrix}\right.\)
d)
\(5x=7y\Rightarrow\dfrac{x}{7}=\dfrac{y}{5}=\dfrac{y-x}{5-7}=\dfrac{18}{-2}=-9\)
\(\Rightarrow\left\{{}\begin{matrix}x=-9.7=-63\\y=-9.5=-45\end{matrix}\right.\)
A) dặt x/5=y/7=k(k≠0)
X/5=k;x=5.k
y/7=k;y=7.k
Có x.y=140
5.k.7.k=140
35k2=140;k2=4
K=±2
vs k=2thì:x=5.2=10;y=7.2=14
vsk=-2thì:x=5.(-2)=-10;y=7.(-2)=-14