Question

b1 tìm số tự nhiên x bt 

a, 3x X +122=21

b,(36-X):2=10

c, 36-X:2 = 10

Answer 1

a, 3x X +122=21

\(3xX=21-122\)

\(3xX=-101\)

\(X=-101:3\)

\(X=-\frac{101}{3}\)

b,(36-X):2=10

\(36-X=10x2\)

\(36-X=20\)

\(X=36-20\)

\(X=16\)

c, 36-X:2 = 10

\(36-X:2=10\)

\(X:2=36-10\)

\(X:2=26\)

\(X=26x2\)

\(X=52\)

Answer 2

a.3xX+122=21

   3xX        =21-122

   3xX        =-101

       X       =-101:3

       X       =\(\frac{-101}{3}\)