Question

b ) \(\frac{6x-3}{5x^2+x}.\frac{25x^2+10x+1}{1-8x^3}\)

Answer 1

\(\frac{6x-3}{5x^2+x}\cdot\frac{25x^2+10x+1}{1-8x^3}\)

\(=\frac{3\left(2x-1\right)}{x\left(5x+1\right)}\cdot\frac{\left(5x+1\right)^2}{\left(1-2x\right)\left(1+2x+4x^2\right)}\)

\(=-\frac{3\left(5x+1\right)}{x\left(1+2x+4x^2\right)}\)

Answer 2

\(\frac{6x-3}{5x^2+x}.\frac{25x^2+10x+1}{1-8x^3}\)

\(=\frac{3\left(2x-1\right)\left(5x+1\right)^2}{x\left(5x+1\right)\left(1-2x\right)\left(1+2x+4x^2\right)}\)

\(=-\frac{3\left(5x+1\right)}{x\left(1+2x+4x^2\right)}\)