Question

a,(y/3-5)^2000=(y/3-5)^2008

b,(x-5)^2=(1-3x)^2

c,1/3*3^x+5*3^x-1=162

d, 2^x+2^x+3=144

e,(x-1)^3=(X-1)^4

g,(x-1)^x+1=(x-1)^x+2

nhanh nha đang cần gấp lắm đó!! ^.^

Answer 1

th1: \(\left(\frac{y}{3}-5\right)^{2008}-\left(\frac{y}{3}-5\right)^{2000}=0\)

\(\left(\frac{y}{3}-5\right)^{2000}.\left[\left(\frac{y}{3}-5\right)^8-1\right]=0\)

\(=>\orbr{\begin{cases}\left(\frac{y}{3}-5\right)^{2000}=0\\\left(\frac{y}{3}-5\right)^{2008}-1=0\end{cases}}\)

\(=>\orbr{\begin{cases}\frac{y}{3}=5=>y=15\\\frac{y}{3}=6=>y=18,\frac{y}{3}=4=>y=12\end{cases}}\)

Vậy ...

P/S: cái đoạn\(\left(\frac{y}{3}-5\right)^{2008}-1=0\)vì số mũ chẵn nên y=18 hay bằng 12 nha!