Vui lòng viết yêu cầu bài :>
a, (x-2)(3x+5)=(2x-4)(x+1)
<=> (x-2)(3x+5)-2(x-2)(x+1)=0
<=>(x-2)(3x+5-2x-2)=0
<=>(x-2)(x+3)=0
\(\Leftrightarrow\orbr{\begin{cases}x-2=0\\x+3=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=2\\x=-3\end{cases}}}\)
b, (2x+5)(x-4)=(x-5)(4-x)
<=>(2x+5)(x-4)-(x-5)(4-x)=0
<=>(x-4)(2x+5+x-5)=0
<=>(x-4)3x=0
\(\Leftrightarrow\orbr{\begin{cases}x-4=0\\3x=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=4\\x=0\end{cases}}}\)