Giải:
a) \(x-\dfrac{-1}{5}=3+\dfrac{-3}{2}\)
\(x-\dfrac{-1}{5}=\dfrac{6}{2}+\dfrac{-3}{2}\)
\(x-\dfrac{-1}{5}=\dfrac{3}{2}\)
\(x=\dfrac{3}{2}+\dfrac{-1}{5}\)
\(x=\dfrac{13}{10}\)
\(\text{Vậy }x=\dfrac{13}{10}\)
b) \(3x-\dfrac{5}{6}=\dfrac{-14}{21}:\dfrac{2}{7}\)
\(3x-\dfrac{5}{6}=\dfrac{-14}{21}.\dfrac{7}{2}\)
\(3x-\dfrac{5}{6}=\dfrac{-7}{3}\)
\(3x=\dfrac{-7}{3}+\dfrac{5}{6}\)
\(3x=\dfrac{-3}{2}\)
\(x=\dfrac{-3}{2}:3\)
\(x=\dfrac{-3}{2}.\dfrac{1}{3}\)
\(x=\dfrac{-1}{2}\)
\(\text{Vậy }x=\dfrac{-1}{2}\)
a) x + 1/5 = 3/2
x = 3/2 - 1/5
x = 13/10
Vậy x = 13/10
b) 3x - 5/6 = -7/3
3x = -7/3 + 5/6
3x = -3/2
x = -1/2
Vậy x= -1/2
