a, \(5-\left(\frac{a}{b}+\frac{1}{2}\right)=2\frac{1}{3}\) => \(\frac{a}{b}+\frac{1}{2}=5-2\frac{1}{3}\) => \(\frac{a}{b}+\frac{1}{2}=\frac{8}{3}\) => \(\frac{a}{b}=\frac{8}{3}-\frac{1}{2}\) => \(\frac{a}{b}=\frac{13}{6}\)
b, \((\frac{3}{4}+2\frac{1}{2}):\frac{3}{5-3}=\left(\frac{3}{4}+\frac{5}{4}\right):\frac{3}{5}-1=\frac{9}{4}:\frac{-2}{5}=\frac{-45}{8}\)
a, 5-(\(\frac{a}{b}\)+\(\frac{1}{2}\))=2\(\frac{1}{3}\)
<=>5-\(\frac{a}{b}-\frac{1}{2}\)=\(\frac{7}{3}\)
<=>\(\frac{a}{b}=5-\frac{1}{2}-\frac{7}{3}\)
<=>\(\frac{a}{b}=\frac{13}{6}\)
b,(\(\frac{3}{4}\)+2\(\frac{1}{2}\)):\(\frac{3}{5}\)-3
=(\(\frac{3}{4}\)+\(\frac{5}{2}\)).\(\frac{5}{3}\)-3
=\(\frac{23}{4}\).\(\frac{5}{3}\)-3
=\(\frac{115}{12}\)-3
=\(\frac{115-36}{12}\)
=\(\frac{79}{12}\)
a) \(5-\left(\frac{a}{b}+\frac{1}{2}\right)=2\frac{1}{3}\)
\(\Rightarrow5-\left(\frac{a}{b}+\frac{1}{2}\right)=\frac{7}{3}\)
\(\Rightarrow\frac{a}{b}+\frac{1}{2}=5-\frac{7}{3}\)
\(\Rightarrow\frac{a}{b}+\frac{1}{2}=\frac{8}{3}\)
\(\Rightarrow\frac{a}{b}=\frac{8}{3}-\frac{1}{2}\)
\(\Rightarrow\frac{a}{b}=\frac{13}{6}\)
Vậy \(\frac{a}{b}=\frac{13}{6}\)
b) \(\left(\frac{3}{4}+2\frac{1}{2}\right):\frac{3}{5}-3\)
\(=\left(\frac{3}{4}+\frac{5}{2}\right):\frac{3}{5}-3\)
\(=\frac{13}{4}:\frac{3}{5}-3\)
\(=\frac{65}{12}-3\)
\(=\frac{29}{12}\)
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