a)\(\sqrt{\sqrt{\left(\sqrt{3-1}\right)^4}}\)\(=\sqrt{\left(\sqrt{3-1}\right)^2}\)
\(=\sqrt{3-1}=\sqrt{2}\)
b)\(\sqrt{\sqrt{x^4}}=\sqrt{x^2}=x\)
a)\(3\sqrt{40\sqrt{12}}+4\sqrt{\sqrt{75}}-5\)\(\sqrt{5\sqrt{48}}\)
b)\(\sqrt{8\sqrt{3}}+3\sqrt{20\sqrt{3}}-2\sqrt{45\sqrt{3}}\)
c)\(\left(\sqrt{x}-1\right).\left(x+\sqrt{x}+1\right)\left(x\ge0;y\ge0\right)\)
d)\(\left(\sqrt{x}+1\right)\left(x+1-\sqrt{x}\right)\left(x\ge0;y\ge0\right)\)
e)\(\left(\sqrt{x}+y\right)\left(x+y^2-y\sqrt{2}\right)\left(x\ge0;y\ge0\right)\)
Các b ơi giúp m vs
Câu 1: A = \(\frac{1}{2\sqrt{x}}+\frac{1}{2-\sqrt{x}}-\frac{2\sqrt{x}}{4-x}\left(x\ne4,x\ge0\right)\)0 và B = \(\left(\sqrt{2}+\sqrt{3}\right)\sqrt{2}-\sqrt{6}+\frac{\sqrt{333}}{\sqrt{111}}\)
a. Rút gọn A và B
b. Tìm x để A = B
Rút gọn
a)\(3\sqrt{40\sqrt{12}}+4\sqrt{\sqrt{75}}-5\)\(\sqrt{5\sqrt{48}}\)
b)\(\sqrt{8\sqrt{3}}+3\sqrt{20\sqrt{3}}-2\sqrt{45\sqrt{3}}\)
c)\(\left(\sqrt{x}-1\right).\left(x+\sqrt{x}+1\right)\left(x\ge0;y\ge0\right)\)
d)\(\left(\sqrt{x}+1\right)\left(x+1-\sqrt{x}\right)\left(x\ge0;y\ge0\right)\)
e)\(\left(\sqrt{x}+y\right).\left(x+y^2-y\sqrt{2}\right)\left(x\ge0;y\ge0\right)\)
Giúp mình với:
Cho b/t A=\(\frac{\sqrt{x}}{\sqrt{x}+3}+\frac{2\sqrt{x}}{\sqrt{x}-3}-\frac{3\left(x+3\right)}{x-9}\) (\(x\ge0\) ; \(x\ne9\) )
Rút gọn b/t A rồi tính giá trị tại x= \(2\left(4+\sqrt{15}\right)\left(\sqrt{10}-\sqrt{6}\right)\sqrt{4-\sqrt{15}}\)
Mai Kt rồi :( :( :(
a) tìm GTLN A= \(1-\sqrt{2x-x^2+1}\)
b) tìm GTNN B=\(\sqrt{x-2\sqrt{x-3}}\)
c) tìm GTNN C=\(\sqrt{\left(x-2017\right)^2+\sqrt{\left(x-1\right)^2}}\)
m.n help me vs nha......
Bài 1:
Cho \(x=\frac{\sqrt{\left(4+2\sqrt{3}\right)}-\sqrt{3}}{\left(\sqrt{5}+2\right)\sqrt[3]{17\sqrt{5}-38}-2}\)
Tính \(P=\left(x^2+x+1\right)^{2013}+\left(x^2+x-1\right)^{2013}\)
Giải giúp mk vs ạ thanks m.n nhìu nà !!!!! :)))
Tất cả đều có điều kiện \(x\ge0\)
a,\(\sqrt{x^2-6x+9}+x=11\)
b,\(\sqrt{3x^2-4x+3=1-2x}\)
c,\(\sqrt{16\left(x+1\right)}-\sqrt{9\left(x+1\right)}=4\)
d,\(\sqrt{9x+9}+\sqrt{4x+4}=\sqrt{x+1}\)
\(B=\sqrt[3]{\frac{x^3-3x+\left(x^2-1\right)\sqrt{x^2-4}}{2}}+\sqrt[3]{\frac{x^3-3x-\left(x^2-1\right)\sqrt{x^2-4}}{2}}\\ vs\\ x=\sqrt[3]{2015}\)
A = \(\frac{\left(1+\sqrt{x}\right)^2-4\sqrt{x}}{\sqrt{x}-1}\left(x\ge0\right)\left(x\ne1\right)\)
B = \(\frac{3+2\sqrt{3}}{\sqrt{3}}+\frac{1}{\sqrt{3}-\sqrt{2}}+\frac{2+\sqrt{2}}{\sqrt{x}+1}\)
Tìm các giá trị của x để A = B
