\(\frac{1}{3}.\frac{1}{x}+\left(\frac{1}{x}+1\right).\frac{2}{5}=\frac{9}{5}\)
\(\Rightarrow\frac{1}{3x}+\left(\frac{1}{x}+\frac{x}{x}\right).\frac{2}{5}=\frac{9}{5}\)
\(\Rightarrow\frac{1}{3x}+\frac{1+x}{x}.\frac{2}{5}=\frac{9}{5}\)
\(\Rightarrow\frac{1}{3x}+\frac{2\left(1+x\right)}{5x}=\frac{9}{5}\)
\(\Rightarrow\frac{1}{3x}+\frac{2+2x}{5x}=\frac{9}{5}\)
\(\frac{5}{15x}+\frac{6+6x}{15x}=\frac{9}{5}\)
\(\Rightarrow\frac{5+6+6x}{15x}=\frac{3.9x}{15x}\)
\(\Rightarrow\frac{11+6x}{15x}=\frac{27x}{15x}\)
\(\Rightarrow11+6x=27x\)
\(\Rightarrow21x=11\)
\(\Rightarrow x=\frac{11}{21}\)
Vậy \(x=\frac{11}{21}\)
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