ta có:\(x-\frac{1}{4}=\frac{5}{8}\cdot\frac{2}{3}\)
=>\(x-\frac{1}{4}=\frac{5}{12}\)
=>\(\frac{2}{3}\)
b)\(\frac{x}{126}=\frac{-20}{63}\)
=>\(\frac{x}{126}=\frac{-40}{126}\)
=>x=-40
a)x-1/4=5/12
x=5/12+3/12
x=2/3
b)x/126=-20/63
x=(-20/63)*126
x=-40
a)\(x-\frac{1}{4}=\frac{5}{8}.\frac{2}{3}\)
\(x-\frac{1}{4}=\frac{5}{12}\)
\(x=\frac{5}{12}+\frac{1}{4}\)
\(x=\frac{2}{3}\)
b)\(\frac{x}{126}=\left(\frac{-5}{9}\right).\frac{4}{7}\)
\(\frac{x}{126}=\frac{-20}{63}\)
\(\Rightarrow x.63=\left(-20\right).126\)
\(\Rightarrow x.63=\left(-2520\right)\)
\(\Rightarrow x=\left(-2520\right):63\)
\(\Rightarrow x=\left(-40\right)\)