Question

ai giúp mih với mai là mih cần rồi

giải các pt

a) (1-2x)^2=(3x-2)^2 

b) (x-2)^3 +(5-2x)^3

Answer 1

\(\left(1-2x\right)^2=\left(3x-2\right)^2\)

\(=\left(1-2x\right)^2-\left(3x-2\right)^2=0\)

\(\left(1-2x-3x+2\right)\left(1-2x+3x-2\right)=0\)

\(\left(3-5x\right)\left(x-1\right)=0\)

\(\Rightarrow3-5x=0\) \(x-1=0\)

\(\Rightarrow x=\frac{3}{5}\)  or \(x=1\)

b)\(\left(x-2\right)^3+\left(5-2x\right)^3\)

=\(\left(x-2+5-2x\right)\left(\left(x-2\right)^2-\left(x-2\right)\left(5-2x\right)+\left(5-2x\right)^2\right)\)

\(\left(3-x\right)\left(x^2-4x+4-5x+2x^2+10-4x+25-20x+4x^2\right)\)

(\(\left(3-x\right)\left(7x^2-33x+39\right)\)

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